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5n^2+17n-910=0
a = 5; b = 17; c = -910;
Δ = b2-4ac
Δ = 172-4·5·(-910)
Δ = 18489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{18489}}{2*5}=\frac{-17-\sqrt{18489}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{18489}}{2*5}=\frac{-17+\sqrt{18489}}{10} $
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